Math, asked by priyapankajsunita, 4 months ago

An object of height 2 cm is placed at a distance
20 cm in front of a concave mirror of focal length
12 cm. Find the position, size and nature of the
image.
Ans. 30 cm in front of mirror, 3 cm​

Answers

Answered by rishabhshah2609
1

This question could be solved using the mirror equation.

The mirror equation is used in cases when we have the distances, heights, and magnification.

It gives us the relationship between focal length, distance of object and distance of image.

Height of the object = 2cm

Distance (u) = 20 cm

Focal length (f) = 12 cm

Mirror Equation 1/f = 1/v + 1/u

On solving, v = 30 cm

Magnification = -hi/ho = v/u

Size of image hi = -v*ho/u hi = 3cm

Since the object is placed between the focus and center, the image will be real, inverted and magnified.

Answered by ItzMissKomal
3

Answer:

Size of object h

o

=2cm

Size of the object h

i

=?

Focal length f=−12cm

Object distance u=−20cm

Image distance v=?

Using mirror formula

f

1

=

v

1

+

u

1

−12

1

=

v

1

+

−20

1

v

1

=

60

−5+3

v=−30cm

Magnification (M)=

h

o

h

i

=

u

−v

=

−20

30

=−1.5

h

i

=−1.5×2=−3cm

Image will be real, inverted and magnified.

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