An object of height 2cm is placed at 20cm distance in front of a concave mirror whose focal length is 15cm.calculate the height of image
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Explanation:
u = - 20 cm,
f = - 15 cm
so, 1/f = 1/v + 1/u
so, 1/-15 = 1/v + 1/-20
1/v = - 1/15 + 1/20
v = - 1/60 cm
Now, we know that m(magnefication) is h2/h1
and - v/u in the case of mirror
We have h1 = 2 cm
So, h2/h1 = - v/u
h2/2 = - (-60)/-20
h2 = - 6 cm
Hence the image distance(v) is - 60 cm,
image size (h2) is - 6 cm
And images is real and inverted ( because v is -ve) and bigger than the object :-)
hope i'm correct
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