Question

An object of height 2cm is placed at 20cm distance in front of a concave mirror whose focal length is 15cm.calculate the height of image​

Answer 1

Explanation:

u = - 20 cm,

f = - 15 cm

so, 1/f = 1/v + 1/u

so, 1/-15 = 1/v + 1/-20

1/v = - 1/15 + 1/20

v = - 1/60 cm

Now, we know that m(magnefication) is h2/h1

and - v/u in the case of mirror

We have h1 = 2 cm

So, h2/h1 = - v/u

h2/2 = - (-60)/-20

h2 = - 6 cm

Hence the image distance(v) is - 60 cm,

image size (h2) is - 6 cm

And images is real and inverted ( because v is -ve) and bigger than the object :-)

hope i'm correct

Answer 2

Answer:

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Explanation:

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