Physics, asked by AxeMello, 4 months ago

An object of height 2cm is placed at a distance of 10cm in front of a lens of power (-10) dioptre. Illustrate only with the help of diagram only to find out the nature and size of the image.​

Answers

Answered by totalgaming0
1

Answer:

Given that,

Focal length f=

2

R

Radius of curvature R=30

Object distance u=10cm

Height of object h

o

=2cm

From the mirror formula,

f

1

=

v

1

+

u

1

v

1

=

u

1

f

1

v

1

=

10

1

30

2

v

1

=

30

3−2

v=−30cm

Now, the magnification is

m=

u

−v

m=

10

30

m=3

Now, the height of image

m=

h

o

h

i

3=

2

h

i

h

i

=6cm

Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3

Explanation:

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