An object of height 2cm is placed at a distance of 10cm in front of a lens of power (-10) dioptre. Illustrate only with the help of diagram only to find out the nature and size of the image.
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Answer:
Given that,
Focal length f=
2
R
Radius of curvature R=30
Object distance u=10cm
Height of object h
o
=2cm
From the mirror formula,
f
1
=
v
1
+
u
1
−
v
1
=
u
1
−
f
1
−
v
1
=
10
1
−
30
2
−
v
1
=
30
3−2
v=−30cm
Now, the magnification is
m=
u
−v
m=
10
30
m=3
Now, the height of image
m=
h
o
h
i
3=
2
h
i
h
i
=6cm
Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3
Explanation:
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