Question

An object of height 2cm is placed at a distance of 12cm infront of a concave mirror of focal length 15cm find the position, nature, and height of the image

Answer 1

Given:

f=(-15cm)

u=(-12cm)

h(object)=2cm

using mirror formula,

1/f=1/v+1/u

1/(-15)-1/12=1/v

by calculating

1/v=1/60

v=60cm

using magnification formula

-v/u=h(image)/h(object)

by cross multiplying h(image) =10cm

the image obtained is virtual and erect