An object of height 3 cm is placed 60 cm from a
convex mirror of focal length 15 cm. Position and
nature of image will be
(option)
1)16 cm, virtual and erect
3)16 cm, real and inverted
3) 12 cm, real and inverted
4) 12 cm, virtual and erect
Answers
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1
Answer:
Given,
Radius of curvature, R=40cm
Object distance, u=30cm
Object height, h
o
=3cm
The focal length of the mirror=f=−
2
R
=−20cm
From mirror equation,
v
1
+
u
1
=
f
1
⟹
v
1
+
−30
1
=
−20
1
⟹v=−60cm
The magnification, M=
u
−v
=−
−30
−60
=−2
Hence the image is inverted, enlarged, real and its size is 2×3cm=6cm.
Explanation:
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