Question

An object of height 3cm is placed at 15 cm from a concave lens of focal length 10. find the size of the image​

Answer 1

h1=3cm

u=-15cm

f=-10cm

Now,

1/f=1v+1/u

-1/10=1/v-1/15

1/v=1/15-1/10

1/v=2/30-3/30

1/v=-1/30

Therefore,

v=-30cm

Therefore,

h2/h1=-v/u

h2/3=-(-30)/-15

h2/3=-2

Therefore, h2=-6cm

Therefore the size of the image is 6cm and it below the principal focus.

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