Question

An object of height 4.0 cm is placed at a distance of
16 cm from concave lens of focal length 10 cm. Find
the position, size and nature of the image formed.

Answer 1

Answer:

answer is = 2

Explanation:

Object distance u=−30 cm

Focal length of convex lens f=20 cm

Height of object h

o

=4 cm

Using lens formula :

v

1

−

u

1

=

f

1

∴

v

1

−

−30

1

=

20

1

⟹ v=60 cm

Magnification

h

o

h

i

=

u

v

⟹

4

h

i

=

−30

60

⟹ h

i

=−8 cm

Ratio of size of image to that of object =

∣h

o

∣

∣h

i

∣

=

4

8

=2