an object of height 4 cm is placed at a distance of 12cm in front of a concave mirror of focal length 24 cm find the nature and size of the image
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Explanation:
h=4cm
u=-12cm
f=-24cm
1/v+1/u=1/f (MIRROR FORMULA)
1/v=1/f-1/u
1/v=-1/24+1/12(SIDE CHANGE AND SIGN CHANGE)
1/v=lcm =48
now,
1/v=-2+4/48
1/v=2/48
1/v=1/24
V = -24
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