Question

An object of height 4 cm is placed at a distance of 20 CM in front of a lens of focal length 10 cm which always forms virtual image. Find image position, height of image, nature of image​

Answer 1

Answer:

Focal length f=−20 cm

Object distance u=−50 cm

Using

v

1

−

u

1

=

f

1

Or

v

1

−

(−50)

1

=

−20

1

We get v=−14.3 cm

Since, v is negative. So image formed is virtual.

Hence, virtual image is formed at a distance of 14.3 cm in front of the lens.