Question

an object of height 4 cm is placed on the principal axis at a distance of 20 cm in front of a convex lens of focal length 30 cm. find the distance of the image from the lens,its height and nature.​

Answer 1

Answer:

142

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Answer 2

Explanation:

u = -20

f = 30

1/v-1/u = 1/f

1/v = 1/f+1/u

1/v = 1/30+(-1/20)

1 /v = 1/30-1/20

1/v = 2-3/60

1/v = -1/60

v = -60

m = h'/h = v/u

h' = v/u ×h

= -60/-20×4

= 12 cm

v= -60

h' = 12

nature of image = as image will be formed at the side where object is placed. So, image formed is virtual,erect and magnified