An object of height 4cm is placed in front of aconvex lens of focal length 20cm.If the object distance is 40cm , find the nature, position and size of the image. Calculate the magnification
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Answer:
Step-by-step explanation:
1/v-1/u= 1/f
1/v+1/40 = -1/20
1/v=-1/20-1/40
1/v=-60/800
1/v=-6/80
v=-40/3
magnification=v/u
-40/3/-20
2/3
hi/ho=2/3
hi=2ho/3
hi=2/3*4
hi=8/3
nature of image is virtual
upright
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