Question

An object of height 4m is placed
at a distance of 15 cm in front of a concave lens of power - 10 D. Find the size of the image






Plzz ans fast ​

Answer 1

Explanation:

ANSWER

h0=4cm

u=−15cm

P=−10 D⇒f=10−1m

We know: f1=V1−u1

So, −10=V1+0.151

or, V1=−110−0.151=−0.151.5−1

or, V1=0.15−2.5

or, V=2.5−0.15m

So, m=uv=2.5×−15−0.15 =2501m=0.4 cm

or, 

Answer 2

Answer:

h

0

=4cm

u=−15cm

P=−10 D⇒f=

10

−1

m

We know:

f

1

=

V

1

−

u

1

So, −10=

V

1

+

0.15

1

or,

V

1

=−

1

10

−

0.15

1

=−

0.15

1.5−1

or,

V

1

=

0.15

−2.5

or, V=

2.5

−0.15

m

So, m=

u

v

=

2.5×−15

−0.15

=

250

1

m=0.4 cm

or,

4

h

i

=0.4 cm

or, h

1

=1.6 cm