an object of height 5 centimetre is held 20 CM away from the converging lens of focal length 10 cm find the position nature and size of the image formed
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Put the values in formula
1/f = 1/v + 1/u
1/10 + 1/20 = 1/v
1/v = 3/20
v = 20/3 = 6.67
1/f = 1/v + 1/u
1/10 + 1/20 = 1/v
1/v = 3/20
v = 20/3 = 6.67
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