Question

an object of height 5 centimetre is placed at 10 cm in front of convex lens of focal length 15 cm find the height of the image nature of the image and position of the image​
plzz solve the full question ​

Answer 1

Answer:

Given –

• Height of the Image = 5 cm.
• Object Distance = -10 cm.
• Focal length of the mirror = 15 cm.
• Convex lens.

To Find –

• Nature of the Image.
• Height of the Image.
• Position of the Image.

Solution –

Lens Formula : 1/v - 1/u = 1/f.

➸ 1/v - 1/-10 = 1/15

➸ 1/v + 1/10 = 1/15

➸ 1/v = 1/15 - 1/10

➸ 1/v = (10 -15)/150

➸ 1/v = -5/150

➸ 1/v = -1/30

➸ v = -30 cm

Hence, the nature of the image is virtual and erect.

The size of the image is enlarged.

The position of the image is on the same side of the lens as the object.

Magnification = v/u =h'/h

➸ 30/-10 = h'/5

➸ 3 = h'/5

➸ Height of the Image = 15 cm