Question

An object of height 5 cm is kept at 80 CM in front of a concave mirror of focal length 40 cm. Find the position of the image,nature of the image and magnification produced by the mirror.

Answer 1

Given:
________

h(object height)=5cm
u (object distance)=-80cm
f (focal length)=-40cm

By using mirror formula:
___________________

1/f=1/v+1/u
after putting value of u and f we get v

v=-80cm

M (magnification)=-v/u
m=-(-80)/-80
m=-1

that is image is real and inverted...

h/h'=m
5/h'=-1
h'=-5

hope it helps u