Question

An object of height 5 cm is placed at a distance of 10 cm from convex mirror of focal length 15 cm. Find the position, nature and size of an image.Solve the given problem.
(Ans:Virtual, erect and diminished image at a distance 6 cm behind the mirror. Height of image = 3 cm)

Answer 1

We School 26 as equal to 3 and the image is a virtual and erect.

Answer 2

Answer:

+ 6 cm

Explanation:

Given :

Object distance = - 10 cm

Focal length = + 15 cm

We have to find image distance.

We know :

1 / f = 1 / v + 1 / u

1 / v = 1 / f - 1 / u

1 / v = 1 / 15 + 1 / 10

1 / v = 1 / 6

v = + 6 cm

Hence .image distance is 6 cm from the mirror behind it.

The image is erect and virtual.