an object of height 5 cm is placed at a distance of 30 cm from the convex lensfocal length 10 cm the height of image of the object is
a)2cm
b)2.5cm
C)1cm
d)1.5cm
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Given :-
- height of object, h₁ = 5 cm
- position of object, u = - 30 cm
- focal length of convex lens, f = 10 cm
To find :-
- height of image , h₂ = ?
Formula used :-
- Lens formula
1 / f = 1 / v - 1 / u
- Formula for magnification of lens
m = v / u = h₂ / h₁
( where u is the position of object , v is the position of image , f is the focal length of lens , m is the magnification , h₂ is the height of image , h₁ is the height of object )
Solution :-
Calculating position of image using Lens formula
→ 1 / f = 1 / v - 1 / u
→ 1 / 10 = 1 / v - 1 / (-30)
→ 1 / v = 1 /10 + 1 / (-30)
→ 1 / v = ( 3 - 1 ) / 30
→ 1 / v = 2 / 30
→ v = 15 cm
Calculating height of image using formula for magnification of lens
→ v / u = h₂ / h₁
→ 15 / (-30) = h₂ / 5
→ h₂ = -2.5 cm
Therefore,
Height of image of the object will be 2.5 cm .
(negative sign in h₂ = -2.5 cm shows that image formed is inverted)
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OPTION (b) 2.5 cm is correct
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