An object of height 5 cm is placed on the principle of concave mirror of focal length 20 cm. If the virtual image is formed by the concave mirror at a distance of 10 cm from its pole, then find the size of the image.
→Note:- Please don't give any unnecessary answer as well as wrong answer I request to all... and by the way it's a question of class 10's sample papers.
Answers
Answered by
3
Explanation:
Given that,
Height of the object, h = 5 cm
Object distance, u = -20 cm
Image distance, v =10 cm (virtual image)
Let h' is the size of image. The magnification of mirror is given by :
m=\dfrac{-v}{u}=\dfrac{h'}{h}m=
u
−v
=
h
h
′
\dfrac{-(10)}{-20}=\dfrac{h'}{5}
−20
−(10)
=
5
h
′
h' = +2.5 cm
So, the height of the image is 2.5 cm. Hence, this is the required solution.
Learn more
Mirror's formula
Similar questions