An object of height 5 cm is placed perpendicular to the principal axis of a concave mirror of a focal length 10 cm. If the distance of the object from the pole of a mirror is 20cm determine position, nature and size of image..
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Answer:
f=-10cm
u=-20cm
v=?
using .1/f=1/v-1/u
we get ,
1/v=1f+1/u
= 1/-10+1/(-20)
= -2-2/20
=-(3)/20
v= -20/3cm
now,
m=h1/h0 =v/u
= h1=V/U*h0
= 20/3*20*5
= 5/3
= 1.6 cm
the image found is virtual and diminished
Explanation:
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Answered by
0
Answer:
Answer:
f=-10cm
h1=5 cm
u=-20cm
v=?
using .1/f=1/v-1/u
we get ,
1/v=1f+1/u
= 1/-10+1/(-20)
= -2-2/20
=-(3)/20
v= -20/3cm
now,
m=h1/h0 = -v/u
= h1= -v*h0/u
= -(-20)*5/3*20
= 5/3
= 1.6 cm
the image found is virtual and diminished
thank you
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