Question

An object of height 5 cm is placed to principal axis
concave Lense of focal length 10cm distance of object of optical centre of length 20 cm determine position
size nature​

Answer 1

Answer:

not clear ..what u want to ask ..

resend this question

Explanation:

if the question is like..

focal length =-10

object's distance =-20

Answer 2

Answer:f=-10cm

u=-20cm

v=?

using .1/f=1/v-1/u 

we get ,

1/v=1f+1/u

= 1/-10+1/(-20)

= -2-2/20

=-(3)/20

v= -20/3cm

now,

m=h1/h0 =v/u

= h1=V/U*h0

= 20/3*20*5

= 5/3

= 1.6 cm 

the image found is virtual and diminished 

hope it helped u ^_^

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Explanation: