Question

an object of height 5cm is kept as a distance of 25cm from a concave mirror of focus 10 cm find the position size and nature of image?

Answer 1

Hi !

Object height = h = +5cm
Image distance = u = -25 cm
Focal length = f = -10 cm
Image distance = v = ?

Mirror formula ,

1/v + 1/u = 1/f

1/v = 1/f - 1/u
       = -1/10 - (-1/25)
       = -1/10 +1/25
       = -5 +2/50
       = -3/50

v = -50/3
   = -16.6 cm (approx.)

m = -v/u
    = -(-16.6)/-25
    = -0.664

As the magnification(m) is negative , the image formed is real,inverted and is at a distance of 16.6 cm from the mirror.



The image is real , inverted and is at a distance of 16.6 cm from the mirror.