An object of height 5cm is placed 20cm in front of pin hole camera from a cubic box of side 6cm . Determine the height of the image formed
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Let AB be the height of the object. Let M be the midpoint of AB. Let CD be the height of the image. Let N be the midpoint of CD. Let O be the pinhole. Align the points M, O, & N. MO = 50 cm and NO = 10 cm. MB = 20/2 = 10 cm. Triangles BMO and CNO are similar because <BOM = <CON (vertically opposite) and <M = <N = 90. The sides of similar triangles are proportional. Then: CN / BM = NO / MO →
CN / 10 = 10 / 50 → CN = 2 cm. The height of the image therefore is 4 cm.
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