An object of height 5cm is placed perpendicular to the principal axis of concave lens of focal length 10cm.If the distance of the object from the optical centre of the lens is 20cm,determine the position,nature and size of the image formed using the lens formula.
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the answer is here there you go
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hello!! friend!
here's ur answer:-
f=-10cm
u=-20cm
v=?
using .1/f=1/v-1/u
we get ,
1/v=1f+1/u
= 1/-10+1/(-20)
= -2-2/20
=-(3)/20
v= -20/3cm
now,
m=h1/h0 =v/u
= h1=V/U*h0
= 20/3*20*5
= 5/3
= 1.6 cm
the image found is virtual and diminished
hope it helped u ^_^
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