Question

an object of height 5cm is placed perpendicular to the principal axis of concave lens of length 10 cm if the distance of the object from the optical centre of lens is 20 cm determine the position ,nature and size of image formed using the lens formula

pLEZZZZZ ANSWER IT!1

Answer 1

hello!! friend!

here's ur answer:-

f=-10cm
u=-20cm
v=?

using .1/f=1/v-1/u 
we get ,

1/v=1f+1/u
= 1/-10+1/(-20)

= -2-2/20
=-(3)/20

v= -20/3cm
now,
m=h1/h0 =v/u

= h1=V/U*h0
= 20/3*20*5
= 5/3
= 1.6 cm 

the image found is virtual and diminished 

hope it helped u ^_^

Answer 2

Answer:

Explanation:

Given :-

f = - 10 cm

u = - 20 cm

v = ?

Solution :-

Using, 1/f = 1/v - 1/u, we get

1/v = 1/f + 1/u

⇒ 1/v = 1/- 10 + 1/(- 20)

⇒ 1/v = - 2 - 1/20

⇒1/v = - (3/20)

⇒ v = - 20/3 cm

m = h/h' = v/u

h = v/u × h'

⇒ h = 20/3 × 20

⇒ h = 5/3

⇒ h = 1.6 cm.

Hence, The position of the image is 1.6 cm.

Image if virtual and diminished.