An object of height 5cm is placed perpendicular to the principle axis of a convex lens of 'f' 10cm. If the distance of the object from 'o' is 20cm, determine the position, nature and size of the object
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Answer:Given :-
f = - 10 cm
u = - 20 cm
v = ?
Solution :-
Using, 1/f = 1/v - 1/u, we get
1/v = 1/f + 1/u
⇒ 1/v = 1/- 10 + 1/(- 20)
⇒ 1/v = - 2 - 1/20
⇒1/v = - (3/20)
⇒ v = - 20/3 cm
m = h/h' = v/u
h = v/u × h'
⇒ h = 20/3 × 20
⇒ h = 5/3
⇒ h = 1.6 cm.
Hence, The position of the image is 1.6 cm.
Image if virtual and diminished.
Explanation:
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