An object of height 6 cm is held 30 cm away from a converging lens of focal length 10 cm. find the position and nature of the image formed.
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h = 6 cm
u = - 30 cm
f = 10 cm
1/v - 1/u = 1/f
1/v + 1/30 = 1/10
v = 15
so the image is formed on the right side of the lens and it is an real and inverted image.
u = - 30 cm
f = 10 cm
1/v - 1/u = 1/f
1/v + 1/30 = 1/10
v = 15
so the image is formed on the right side of the lens and it is an real and inverted image.
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