An object of height 6 cm is placed at a distance of 24 cm from a concave mirror of focal length 30 cm find position height and nature of image.
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Answer:
Position of image = Behind the mirror
height of image= 30cm
Nature of image= Virtual and erect
Explanation:
h=6cm
u=-24cm
f=-30cm
image height (h¹)=?
image distance (v)=?
1/f= 1/v +1/u
1/-30= 1/v-1/24
by solving this we will get
v=120cm
m=h¹/h= -v/u
by using the above formula we will get
height of the image (h¹)= 30cm
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