An object of height 6 cm is placed at a distance of 5 cm from a plane mirror. Find the size of the
image formed by the plane mirror and also find at what distance the image will be formed?
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Answer:
We know that,
v 1 + u 1
= f 1
u = -15 cm
Focal length = -10 cm
∴ v 1
= −10 1 − (−15)
1
⇒ v 1
= −10 1 + 15
1
= 30 −3+2
=− 30
1
⇒v=−30cm
Magnification (m)= u v
= Object height
Image height
m=− u v
=+ −15 30
=−2
Also, Image height=−2×6=−12 cm
Therefore, a real, inverted and enlarged image of the object is formed beyond the centre of curvature.
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