an object of height 6 cm is placed front of concave lens of focal length 5 cm determine position, size and nature of image if object distance is 10cm ??
Answers
Answer:
Explanation:
An object of height 6 cm is placed perpendicular to the principal axis of a concave lens of focal length 5 cm. ... Thus, the image of size 2 cm will be formed in front of the lens at a distance of 3.33 cm from the lens. The nature of the image is virtual and erect
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Correct Question: an object of height 6 cm is placed front of concave lens of focal length 5 cm determine position, size and nature of image if object distance is 10cm ??
Solution:
h=6cm
f= -5cm
u= -10cm
=>1/v=1/u+1/f
=1/-10+1/-5cm
=-1-2/10cm
=-3/10cm
=>v =-10/3cm
=-3.33cm
Hence,the image will form at the same side of object,3.33cm away from the lens
Now,m=h'/h=v/u
=h'/6=(-10/3)/-10
=h'/6=1/3
=h'=2 Ans
Hence, the size of image is 2cm size of image is 2cm nature of image is real and inverted