Question

an object of height 6 cm is placed perpendicular on the principal Axis for concave mirror at a distance of 15 CM the focal length of concave mirror of 5 cm find the image distance of the magnification and nature of image​

Answer 1

Answer:

In a concave mirror, the magnification is the ratio of the height of the image to the height of the object. The magnification is also equal to the negative of the ratio of the distance of the image from the mirror to the distance of the object from the mirror

Explanation:

Answer 2

Image distance is 7.5 cm. Magnification is -2. It means the image is real and inverted.

Explanation:

Given,

              Height of the object = 6 cm.

              Object distance = 15 cm

              Focal length = 5 cm

         

We know that

                               ⇒ $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

                               ⇒ $\frac{1}{5} = \frac{1}{v} + \frac{1}{15}$

                              ⇒   v = 7.5 cm

Magnification,

                                ⇒ m = $\frac{-v}{u}$

                                ⇒ m = -2

       The image height can be calculated from the magnification which is 12 cm.