An object of height 6 cm is placed perpendicular to the principal axis of a concave lens of focal length 5cm use lens formula to determine the position size and nature of the image if the distance of the object from the lens is 10 centimetre
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Acc. to lens formula
1/f=1/u-1/v
we get
v=-10/3cm or position
nature =smaller than object
size-2cm
since we know rhat m=-v/u=h(i)/h(o)
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