Question

An object of height 6cm is placed perpendicular on principal axis before a concave mirror at a distance 15cm the focal length is 5cm find image distance ,magnification & nature of image

Answer 1

The nature of the image is virtual and erect.

Explanation:

We are given that:

• Height "h" = 6 cm
• focal length " f" = - 5 cm
• Disatnce "u" = - 15 cm
• v = ?  

Solution:

Now using the lens mirror formula.

1 / f = 1 / v + 1 / u  

1 / v = 1 / f -  1 / u

1/v = 1 / 5 - 1 /- 15

1/v = 1 / 5 + 1 / 15

1 / v  = 3 + 1 / 15

V  = 15 / 4

V = 3.75 cm

Magnification = - v / u

M = - 3.75 / - 15

M = 0.25

Thus the nature of image is virtual and erect.