Question

An object of height 6cm is placed perpendicular to the principal axis of concave mirror of focal lens is placed perpendicular to the principal axis of concave lens of focal length 12cm use lens formula to determine the position,size and nature of the image. if the distance of the object from the lens is 12cm.

Answer 1

Answer:

Explanation:

Given An object of height 6cm is placed perpendicular to the principal axis of concave mirror of focal lens is placed perpendicular to the principal axis of concave lens of focal length 12cm use lens formula to determine the position,size and nature of the image. if the distance of the object from the lens is 12cm.

We know that height is h = 6 cm, focal length f = -12 cm, distance of object u = - 12 cm

1/v = 1/u + 1/f  

1/v = 1/-12 + 1/-12

1/v = - 1/6

v = -6

hence image is formed at a distance of 6 cm at the left side of the lens.

Now m = v/u

m = - 6/- 12

m =  1/2

height of image is m x height of object

    = 1/2 x 6

So h = 3 cm

So image is virtual and erect.