Question

an object of height 6cm is placed perpendicular to the principal axis of a concave mirror of focal length f at a distance of 4f .the length of the image will be​

Answer 1

Answer:

2

Explanation:It is a concave mirror so it is negative

Height of the object=6cm

Focal length =f=-f

Radius of curvature is =2*f (f)

=2f

Distance of the object =4f (u) =-4f

That means it is beyond the centre of curvature

Mirror formula:1/v+1/u =1/f

Sub in formula

1/v+-1/4f=-1/f

1/v=-1/f-1/4f

1/v=-4+1/4f

1/v=-3/4f

V=-4f/3

Height of the image = - (v/u) =hi/ho

-1/3=x/6

3x=-6

X=-2

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