Question

an object of height 7 cm is kept at a distance of 25cm in front of a concave mirror the focal length of the mirror is 15 CM at what distance for the mirror should screen be kept so as to get a clear image? what will be the size and nature of the image? Its urgent tomorrow is paper ......... plzzzzzzzz......​

Answer 1

Answer:

Image - Real, Inverted and Enlarged

Explanation:

1/f = 1/v+1/u

1/f - 1/u = 1/v

1/15 - (1/25)

1/15-1/25 = 1/v

5-3/75=1/v

2/75 = 1/v

v= 75/2

v = 37.5cm

Answer 2

Answer:

We use the curved mirror formulae to get the image distance.:

1/f=1/v+1/u

V is object distance and u is image distance.

F is the focal length.

Substituting the values :1/15=1/25+1/u

1/u=1/15-1/25=5-3/75=2/75

U=75/2=37.5cm

We use the object distance and the image distance to get the magnification.

M=37.5/25=×1.5

The image size =1.5×7=10.5cm

The image is real.

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