Question

an object of height 7 cm is kept at a distance of 25cm in front of a concave mirror the focal length of the mirror is 50 cm at what distance from the mirror should screen became so as to get a clear image what will be the size and nature of the object image

Answer 1

Using the mirror formula that is 1/v+1/u=1/f
u= -25cm(because object is towards left)
f= -50cm(same reason)
1/v+1/-25=1/-50
Solving, we get value of 'v' that is the distance the screen should be kept.

Now, image size= (-v*object size)/u. Solve it

This is a special case in concave mirror as the object is between focal length and pole.
Therefore, nature of image= Virtual, enlarged and erect

Answer 2

❤ u=-25cm
f=-50
v=?
1/f=1/v-1/u
1/-50=1/v+1/25
-50=1/v+1/25
-50=1/v+25
-50=25/v
v=-50/25
v=-2