an object of height 8 cm placed at centre of curvature on principal axis then wher do you get the image and what is its height ?
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Answer:
Given :
u=−10cm
R=−8cm=2f
f=−4cm
To find : v
Solution: From mirror formula
u1= f1
v1− 10
1=− 41
v1= 10/4−6
v= 3−20 cm
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