An object of height 8cm is
placed in front of a convex
mirror of radius of curvature
48cm. If a virtual image of
height 2cm is produced behind
the mirror, then the distance
of the image from the mirror is
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Answer:
Given,
mirror type = convex
ho=8cm
f=24cm
hi=2cm
v=?
m=hi/ho
= 2/8
=0.25
m=-v/u
2/8=-v/u
2u=-8v
u=-4v
1/f=1/v+1/u
1/24=1/v + 1/-4v
1/24=1/v-1/-4v
1/24=4-1/4v
1/24=3/4v
4v=72
v=18cm
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