Question

an object of height is 10 centimetre is placed at 6 from a concave mirror the image is obtained at 24 cm and the mirror find the magnification produced by the mirror and the height of the image​

Answer 1

Explanation:

we have mirror equation:

1 /v + 1/ u = 1/ f ............(1)

where v is image to mirror distance, u is object to mirror distance and f is focal length,

1/v + 1/10 = 1/ 5

or v= 10 cm

magnification = -v/u = -10/10 = -1 ; image size is same size of object, real and inverted