Question

An object of height is equal to10cm is kept at a distance 30cm in front of a concave mirror 20cm. find image distance ,nature of image, and magnification.​

Answer 1

Answer:

Thus, the focal length of the concave mirror is 15 cm. (b) Now, if the image is virtual and 3 times magnified, then we have to find the position of the object. Thus, the object should be placed at a distance of 10 cm to get a virtual image three times the height of the object.

Answer 2

Answer:

Here,

u= -30 cm

f= -20 cm

By using mirror formula,

1/v + 1/u = 1/f

1/v + 1/-30 = 1/-20

v= -60 cm

negative sign indicates that image is in front of the mirror

Therefore,

The distance between image and object = 60–30 = 30cm

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Explanation: