Question

an object of hieght 10 cm is placed at centre of curvature of a concave mirror then find the magnification produced by the mirror.​

Answer 1

Answer:

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Answer 2

Answer:

Object distance u=−36 cm

Focal length of concave mirror f=−12 cm

Using mirror formula :

v

1

+

u

1

=

f

1

Or

v

1

+

−36

1

=

−12

1

⟹ v=−18 cm,

Since image position is negative, i.e. image is on the same side of object, which is real space, therefore the image is real.

Step2: Finding Height using Magnification

Magnification

h

o

h

i

=

u

−v

Or

10

h

i

=

−12

−(−18)

⟹ h

i

=−15 cm

Negative height implies that the image is inverted.

Hence, a real and inverted image of height 15 cm is formed at a distance of 18 cm in front of the mirror.

Explanation:

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