Question

An object of hight 2cm is placed at 20cm distance in from of a concave mirror whose focal length is 15cm calculate hight of the mirror​

Answer 1

Explanation:

ANSWER

ANSWERSize of object  ho=2cm

ANSWERSize of object  ho=2cmSize of the object  hi=?

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cm

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cm

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formula

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1−121=v1+−201

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1−121=v1+−201v1=60−5+3

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1−121=v1+−201v1=60−5+3v=−30cm

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1−121=v1+−201v1=60−5+3v=−30cmMagnification (M)=hohi=u−v=−2030=−1.5

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1−121=v1+−201v1=60−5+3v=−30cmMagnification (M)=hohi=u−v=−2030=−1.5hi=−1.5×2=−3cm

ANSWERSize of object  ho=2cmSize of the object  hi=?Focal length  f=−12cmObject distance  u=−20cmImage distance  v=?Using mirror formulaf1=v1+u1−121=v1+−201v1=60−5+3v=−30cmMagnification (M)=hohi=u−v=−2030=−1.5hi=−1.5×2=−3cmImage will be real, inverted and magnified.