Question

an object of length 10 cm is placed at right angles to the principle axes of a mirror bof radius of curvature 60cm such that it's image is virtual ,erect and has length 6cm.What kind of mirror is it and also determine the position of the object​

Answer 1

Answer:

Since the image is virtual, erect and of a smaller size, the given mirror is ‘convex’ (concave mirror does not form an image with the said description). <br> Given R = +60 cm f=R/2=30cm <br> Transverse magnification, <br> m =Further m =<br>v =<br> using<br>u = -20 cm <br> Thus the object is at a distance 20 cm (from the pole) in front of the mirror.

Answer 2

Answer:

Solution :

Since the image is virtual, erect and of a smaller size, the given mirror is ‘convex’ (concave mirror does not form an image with the said description). <br> Given R = +60 cm f=R/2=30cm <br> Transverse magnification, <br> m =

Further m =

<br>

v =

<br> using

<br>

u = -20 cm <br> Thus the object is at a distance 20 cm (from the pole) in front of the mirror.