Question

an object of length 10 cm is placed infront of a curved mirror . the length of the virtual image is 15 cm. Find the refractive index of the medium
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Answer 1

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Class 12

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An object is placed 10 cm away from a glass piece (μ=1.5) of length 20 cm bound by spherical surfaces of radii of curvature 10 cm. Find the position of final image formed after refractions.

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Solution

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It is given that for first surface:

n

1

=1

n

2

=1.5

v

1

=?

u

1

=−10cm

R=+10cm

So,

v

1

n

2

−

u

1

n

1

=

R

n

2

−n

1

Answer 2

In this case, u=−10cm;f=20cm

Since object is placed within focus of a concave mirror, the image will be virtual, up right and enlarged.