An object of length 17 m is placed at a distance of 14 m the image is formed 14 m away from the mirror.
Find the focal length of the mirror, and magnificant of the image. Say wheather it is real or virtual image.
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Answers
It is stated that,
The length of the object (O) = 17 m
The distance of the object (u) = 14 m
The distance of the formed image (v) = (14+14)m
= 28 m
Let, the magnificant of the image be, 'm'
The focal length be, 'f'
We know that,
Magnificant of the image = - v/u
= -28/14
= -2
The magnificant of the image is -2
As the magnificant of the image is negative so, its a real image.
We know that,
1/ focal length = (1/distance of the object) + (1/distance of the formed image)
⇒ 1/f = (1/u) + (1/v)
⇒ 1/f = (1/14) + (1/28)
⇒ 1/f = (1+1)/28 [∵ The L.C.M. of 14 and 28 is 28]
⇒ 1/f = 2/28
⇒ 1/f = 1/28
⇒ f = 14 m
So, the foal length of the mirror is 14 m.
Answer:
Yes
Explanation:
Refer the above attachment.
