Question

An object of length 20cm and width 40cm undergo a thrust of 50 Newton calculate the pressure exerted on it

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Pressure=625\:N/m^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Length = 20 \: cm \\ \\ \tt: \implies Width=40 \: cm \\ \\ \tt: \implies Force(F) =50 \: N \\ \\ \red{\underline \bold{To \: Find :}}\\ \tt: \implies Pressure = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Area \: of \: object = l \times w \\ \\ \tt: \implies Area \: of \: object =20 \times 40 \\ \\ \green{\tt: \implies Area \: of \: object =800 \: cm^{2}= 0.08 \: m^{2}} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Pressure = \frac{Force}{Area} \\ \\ \tt: \implies Pressure = \frac{50}{0.08} \\ \\ \green{\tt: \implies Pressure = 625 \: N/ {m}^{2} }$

Answer 2

Given :-

Length of an object is 20 cm.

Width of the object is 40 cm.

Thrust exerted = 50 N

To find :-

The pressure exerted on the object.

Solution :-

Area of the object = Length*Width

⇒Area = 20*40

⇒Area = 800 cm²

⇒Area = 800/10000 = 0.08 m²

Now, we know,

Pressure = Force/Area

⇒Pressure = 50/0.08

⇒Pressure = 625 N/m² = 625 Pa