Question

An object of length 3 m, width 1 m, and thickness 1 m is immersed in water. It displaces 2 L of water. How much buoyant force is acting on the object? (g = 10 m s-2) *

6N

30N

20N

60N

​

Answer 1

Answer:

20N mark me as brainliest

Answer 2

20,000 N would be the buoyant force.

Given:

(g = 10 m s-2)

(Density of water = 1000 kg/m3)

(1 cubic metre = 1000 litres)​

To find: Buoyant force

Solution:

Displacement is outlined as the change available of an object. It is a heading pile and has a course and importance. It is presented as an dart that points from the offset position to the last position.

For example- If an object moves from A position to B, therefore the object’s position changes. This change available of an object is popular as Displacement.

Distance is the total activity of an object outside some regard to course. We can outline distance concerning by what method much ground an object has coated regardless of allure offset or conclusion point. It is a scalar quantiy.

We can use the equation: to calculate the buoyant force exerted on the object.

Weight of the displaced fluid = buoyant force.

the object has a volume of 3 m × 1 m × 1 m = 3 cubic metres. The volume of the displaced fluid times the water's density times the acceleration due to gravity equals the weight of the displaced fluid.

As a result, the object is under the following buoyant force:

Buoyant force = 2 L×  1000 kg/m3 × 10 m/s2

= 20,000 N

20000N is the force that the thing is experiencing when it floats on the water.

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