Question

an object of length 4 cm is placed at a distance 20cm from a convex lens of focal length 10 cm what is the length and nature of the image


please answer me​

Answer 1

Answer:

Explanation:

u=−10cm  

h1 =4cm

F =20cm

1$\frac{1}{v} - \frac{1}{u} = \frac{1}{f }$

$\frac{1}{v} - \frac{1}{-10} = \frac{1}{20}$

$\frac{1}{v} \frac{1}{20} - \frac{1}{10} = -\frac{1}{20}$

v = -20 (Image is 20cm in front of the convex lens)

$m = \frac{v}{u} = \frac{20}{-10} = -2$

$m = \frac{h2}{h1} = -2$

h2 = -8cm

Image is 8cm in size is real and inverted    

     I HOPE THIS HELPS U A LOT

~ Have a nice day