An object of length 4 cm is placed in front of a concave
mirror at distance 30 cm. The focal length of mirror is 15 cm. (a) Where will the image form? (b) What will be the length of image?
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An object of length 4 cm is placed in front of a concavemirror at distance 30 cm. The focal length of mirror is 15 cm.
a) Where will the image form?
b) What will be the length of image?
H = 4cm, U = -30, F = -15.
(a) using mirror formula, we have
1/v + 1/u = 1/f
therefore, 1/v = 1/f - 1/u
1/v = 1/-15 - 1/-30
1/v = 1/30 - 1/15
1/v = -1/30
therefore, v = -30
Hence, the image will be formed at a distance of 30cm on the same side as the object.
(b) For a mirror, linear magnification is
M = h¹/h = - v/u
therefore, h¹ = - v/u h = -30/-30 *4 = -4cm
Therefore, the length of the image is the same as the object i.e. 4cm but it is inverted in nature.
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