Physics, asked by pbguardian07, 1 month ago

An object of length 5 cm is placed in front of a spherical mirror at the distance of 30cm. The focal length of the mirror is (-15cm). A) determine the nature of mirror, B) where will be the image formed C) what will. Be the size of the image?

Answers

Answered by ss7870381546
1

Explanation:

u= -30cm

f= -15cm

v=?

height of object = 5 cm

1/v+1/u= 1/f

1/v= 1/-15-(1/-30)

= 1/15+1/30

=1/10

v=10cm

nature of image is convex mirror and it is virutual and erect.

m= -v/u

= -10/-30

= 1/3

m= 3cm

m= height of image/ height of object

3 = height of image/5

height of image= 15 cm

Answered by poojipoojitha2004
0

Answer:

Hii

gd evng

can you tell about the meeting??

Similar questions