An object of length 5 cm is placed in front of a spherical mirror at the distance of 30cm. The focal length of the mirror is (-15cm). A) determine the nature of mirror, B) where will be the image formed C) what will. Be the size of the image?
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Explanation:
u= -30cm
f= -15cm
v=?
height of object = 5 cm
1/v+1/u= 1/f
1/v= 1/-15-(1/-30)
= 1/15+1/30
=1/10
v=10cm
nature of image is convex mirror and it is virutual and erect.
m= -v/u
= -10/-30
= 1/3
m= 3cm
m= height of image/ height of object
3 = height of image/5
height of image= 15 cm
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